@don:
will u pls explain why divided by 5 is used ....

On Fri, Sep 16, 2011 at 3:44 PM, prasanth n <[email protected]> wrote:

> @Don:
> thanks a lot
>
> On Sat, Sep 17, 2011 at 12:28 AM, Don <[email protected]> wrote:
>
>> The algorithm is to count them, looping over the number of quarters
>> and dimes. Then it is easy to compute the number of nickles which
>> could be used, and the shortfall is made up with pennies.
>> It is very common to see a recursive solution, but that is not
>> necessary or beneficial when the iterative solution is so simple.
>> Don
>>
>>  int result = 0;
>>  for(int quarters = 0; quarters <= n; quarters += 25)
>>      for(int dimes = 0; (quarters+dimes) <= n; dimes += 10)
>>        result += 1 + (n-quarters-dimes) / 5;
>>
>> On Sep 16, 1:35 pm, prasanth n <[email protected]> wrote:
>> > Given an infinite number of quarters (25 cents), dimes (10 cents),
>> nickels
>> > (5 cents) and pennies (1 cent), write code to calculate the number of
>> ways
>> > of representing n cents.
>> > also do give an algorithm first..
>> >
>> > --
>> > *prasanth*
>>
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>
>
> --
> *prasanth*
>
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