I don't understand your point if y[i] < y[i+1]
how come the slope is positive?
It's just that the i'th line will lie under line i+1th line.


On Sat, Aug 27, 2011 at 5:11 PM, monish001 <[email protected]> wrote:

> If I correctly understood the question, It says:
> 1. 0<= x[i] <=1 for all i and for all x of line i.
> 2. y[i]<y[i+1] means lines have positive slope
>
> If line i is f(x,y): A[i]x + B[i]y -C[i], Use the following concept:
> 1. Find 1 line closest to the given point such that f(x,y) is of same
> sign for both (0,0) and given point.
> 2. Find other line closest to the given point such that f(x,y) is of
> opposite signs for both (0,0) and given point.
>
> To check which line is closest, use the formula which finds the
> (perpendicular) distance between the line and the point.
> I am not sure about the correctness of the following formula:
> If distance of x,y from ax+by=c is d.
>
> d = sqrt(2)*( (a*a + b*b - c) / (a-b) )
>
>
> -Monish
> On Aug 26, 6:19 am, Ankur Garg <[email protected]> wrote:
> > You are given n no. of lines in form of Ax + By = C, basically you are
> given
> > A[i], b[i] and C[i] for line "i".
> > Lines are given in a way such that 0 <= x[i] <= 1 and y[i] < y[i+1] for
> same
> > X.
> > Also, one point (x,y) is given too. Find out the two closest lines to the
> > point such that the point is between them.
> > Given: n - no. of lines
> > a[i] b[i] c[i] - i th line.
> > X Y - Point
> > Output
> > A[i] B[i] C[i]
> > A[j] B[j] C[j]
> > such that the point X,Y is between them.
>
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