@Priya: If 2/3 of the games is 20, then the total number of games is 30. Since 3/4 of 30 is 22.5, to win 3/4 of those 30 games, the team must win 23. That means the team can lose no more than 7. Since the team already has lost 3, it can lose up to 4 of the remaining 10 games.
Dave On Aug 23, 9:22 am, priya ramesh <[email protected]> wrote: > Out of two thirds of the total number of basket -ball matches, a team has > won 17 matches and lost 3 of them. What is the maximum number of matches > that the team can lose and still win three -fourths of the total number of > matches, if it is true that no match can end in a tie? [1] 4 [2] 6 [3] 5 [4] > 3 -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
