No idea how to solve the problem except the brute force O(n3) approach.I am
looking for a better solution than this. Because of O(1) complexity you
cannot copy and sort the input.


A zero-indexed array A consisting of N integers is given. A triplet (P, Q,
R) is triangular if and
A[P] + A[Q] > A[R],
A[Q] + A[R] > A[P],
A[R] + A[P] > A[Q].

For example, consider array A such that

A[0] = 10 A[1] = 2 A[2] = 5
A[3] = 1 A[4] = 8 A[5] = 20
Triplet (0, 2, 4) is triangular.

public int triangle(int[] A)

that, given a zero-indexed array A consisting of N integers, returns 1 if
there exists a triangular triplet for this array and returns 0 otherwise.

Assume that:

N is an integer within the range [0..100,000];
each element of array A is an integer within the
range[-2,147,483,648..2,147,483,647].
For example, given array A such that

A[0] = 10 A[1] = 2 A[2] = 5
A[3] = 1 A[4] = 8 A[5] = 20
the function should return 1, as explained above. Given arrayA such that

A[0] = 10 A[1] = 50 A[2] = 5
A[3] = 1
the function should return 0.
Expected worst-case time complexity: O(n log n)
Expected worst-case space complexity: O(1)

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