instead of that find sum of first n natural number sum ie (n(n+1))/2.;say
NSum
then find the sum of all elements of the array . say ASum
ASUm - NSum = result (no repeated twice).

On Fri, Aug 19, 2011 at 7:30 PM, Sanjay Rajpal <[email protected]>wrote:

> :)
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> *Regards
>
> Sanju
>
> Happy to Help :)*
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>
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