hash map is the solution provided the elements lie in a predefined range..

On Fri, Aug 19, 2011 at 8:46 AM, *$* <[email protected]> wrote:

> true. I agree , we can use additional memory which will be constant
> irrespective of counjt of elements.
>
> But using an hash wont be a constant memory as input can keep on varying.
>
> Thx,
> --Gopi
>
>
> On Fri, Aug 19, 2011 at 8:16 AM, Dipankar Patro <[email protected]>wrote:
>
>> O(1) space means constant space. It doesn't mean you can't use extra
>> space.
>> Refer here:
>> http://stackoverflow.com/questions/2219109/what-does-this-mean-on-steps-and-o1-space
>>
>> According to the question you can definitely use a Hash Table for keeping
>> hit record, as it will be a constant space (provided the range of numbers is
>> known).
>>
>> In case the range of numbers is not known, BST will be close answer. Since
>> only one element will be repeating, the process of making the BST can be
>> stopped when the first repeating element is caught. BUT, this will be O(n)
>> space, as the number of nodes in BST will be n-1 in worst case.
>>
>> On 19 August 2011 07:59, *$* <[email protected]> wrote:
>>
>>> only once
>>>
>>>
>>> On Fri, Aug 19, 2011 at 7:57 AM, saurabh singh <[email protected]>wrote:
>>>
>>>> The element is repeated only once or can be repeated k number of times??
>>>>
>>>> On Fri, Aug 19, 2011 at 7:50 AM, *$* <[email protected]> wrote:
>>>>
>>>>> I think we are using hash , which is like extra spaace , but as per the
>>>>> question , O(s) = 1.
>>>>>
>>>>> Thx,
>>>>> --Gopi
>>>>>
>>>>>
>>>>> On Fri, Aug 19, 2011 at 2:15 AM, icy` <[email protected]> wrote:
>>>>>
>>>>>> #!/usr/bin/ruby -w
>>>>>> #array of unsorted positive integers
>>>>>> # find the [only] one that is duplicated
>>>>>>
>>>>>> arr= [97,2,54,26,67,12,1,19,44,4,29,36,67,14,93,22,39,89]
>>>>>> h = Hash.new(0)
>>>>>>
>>>>>> arr.each {|n|
>>>>>>        h[n]+=1
>>>>>>        (puts n; break) if h[n]==2
>>>>>> }
>>>>>>
>>>>>> #output
>>>>>> #67
>>>>>>
>>>>>> I hope this meets the requirements ;P
>>>>>>
>>>>>> On Aug 18, 3:15 pm, "*$*" <[email protected]> wrote:
>>>>>> > How to find duplicate element (only one element is repeated) from an
>>>>>> array
>>>>>> > of unsorted positive integers..
>>>>>> > time complexity .. O(n)
>>>>>> > space .. o(1).
>>>>>>
>>>>>> --
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>>>>>>
>>>>>
>>>>>
>>>>> --
>>>>> Thx,
>>>>> --Gopi
>>>>>
>>>>>
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>>>>
>>>>
>>>> --
>>>> Saurabh Singh
>>>> B.Tech (Computer Science)
>>>> MNNIT ALLAHABAD
>>>>
>>>>
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>>>
>>>
>>>
>>> --
>>> Thx,
>>> --Gopi
>>>
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>>
>>
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>
>
>
> --
> Thx,
> --Gopi
>
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-- 
*Dheeraj Sharma*
Comp Engg.
NIT Kurukshetra
+91 8950264227

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