yep it will !! any ways nodeptr is another name for pointer to the same structure so you dont need to write struct<name> *nodeptr you can simply write nodeptr *p(say) to declare pointer to the structure
On Tue, Aug 9, 2011 at 8:09 PM, rohit jangid <[email protected]> wrote: > it will give error in line 3 because nodeptr is undefined till that point.. > > On Aug 9, 2011 8:03 PM, "programming love" <[email protected]> > wrote: > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
