that is why i gave BST algo first :)
but rahul wanted me to give O(n) algo

On Jul 31, 1:15 am, Kamakshii Aggarwal <[email protected]> wrote:
> @nivedita :hashing will not work if the range of nos is high
>
> On Sun, Jul 31, 2011 at 1:40 AM, nivedita arora <[email protected]
>
>
>
>
>
>
>
>
>
> > wrote:
> > ok lets think in terms of hashmap of number and frequency
> > we definitly have to maintain an order array .
> > traverse original array ,  we check if its present in hashmap ..if not
> > - 1)add it to hashmap and set frequency to 1 2)add it in order array
> > if yes then increment frequency by 1.
> > searching taking O(1) time .
>
> > now traverse order array..search for corresponding freq and print
>
> > this should take o(n) time...let me know if i faultered anywhere.
>
> > @aditi- pls dont use just arrays..its not efficient way.
>
> > On Jul 31, 12:51 am, rahul mittal <[email protected]> wrote:
> > > @nivedita:can u do this in o(n) time , i suppose your algorithm takes
> > > 0(nlogn) time
>
> > > On Sun, Jul 31, 2011 at 1:14 AM, nivedita arora <
> > [email protected]
>
> > > > wrote:
> > > > @rahul- balanced BST can be maintained.to remove worst case !
> > > > @sukhmeet- i did not gt your method completely ..u are trying to
> > > > maintain hashmap or double dimension array of number and count?
> > > > @aditi- for array we will have overhead of searching if element is
> > > > present or not ..in O(n) time while it will be O(logn) in BST.
> > > >  in array we cannot do binary search as it will not be sorted to
> > > > improve search .
>
> > > > On Jul 31, 12:31 am, rahul mittal <[email protected]> wrote:
> > > > > maintaining the bst of n element in worst case will take n square
> > time
> > > > > complexity ..do we have a better solution for worst case
>
> > > > > On Sun, Jul 31, 2011 at 12:53 AM, sukhmeet singh <
> > [email protected]
> > > > >wrote:
>
> > > > > > nivedita: wts the use to maintaining BST.. if the same purpose can
> > be
> > > > > > fulfilled by an array ..
> > > > > > but this can be a good method if the range of numbers is pretty
> > large..
> > > > den
> > > > > > making a hash count can be difficult..
>
> > > > > > On Sun, Jul 31, 2011 at 12:43 AM, nivedita arora <
> > > > > > [email protected]> wrote:
>
> > > > > >> take a BST whose node has an element of frequency .and another
> > array
> > > > > >> which will store order of elements.
> > > > > >> for each array element search BST if node already exists increase
> > the
> > > > > >> freq count ..other wise  add that element in the order array we
> > took
> > > > > >> and insert new node in BST.
>
> > > > > >> now , scan the order array find its corresponding element in BST
> > and
> > > > > >> its frequency, print it that many times.
>
> > > > > >> let me know if there is any bttr method
> > > > > >> thx!
>
> > > > > >> On Jul 30, 11:58 pm, sukhmeet singh <[email protected]>
> > wrote:
> > > > > >> > maintain a count array of all elements..
> > > > > >> > now traverse the array again and the count array .. and build
> > the
> > > > new
> > > > > >> array
>
> > > > > >> > On Sun, Jul 31, 2011 at 12:24 AM, aditi garg <
> > > > [email protected]
> > > > > >> >wrote:
>
> > > > > >> > > Q1) Given an array with some repeating numbers. Like
> > 12,6,5,12,6
> > > > > >> > > output: 12,12,6,6,5
>
> > > > > >> > > 12 shud come before 6 since it is earlier in list. Please
> > provide
> > > > a
> > > > > >> > > gud algo fr dis
>
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> > > > > --
> > > > > *With Regards *
> > > > > *RAHUL MITTAL*
> > > > > *3rd YEAR*
> > > > > *CSE*
> > > > > *MNNIT ALLAHABAD*
>
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> > > --
> > > *With Regards *
> > > *RAHUL MITTAL*
> > > *3rd YEAR*
> > > *CSE*
> > > *MNNIT ALLAHABAD*
>
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> --
> Regards,
> Kamakshi
> [email protected]

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