Consider the binary representation of 257 which is 100000001 which will be stored in little endain representation as least significant eight bits + most significant eight bits as follows
00000001 | 00000001 now iptr on casting to char will point to least significant eight bits which is 1, when u increment iptr it refers to most sig 8 bits which is also 1 hence the o/p will be : 1 1 hope it helps! On Mon, Jul 25, 2011 at 11:41 AM, aditya kumar <[email protected] > wrote: > main() > { > int i = 257; > int *iPtr = &i; > printf("%d %d", *((char*)iPtr), *((char*)iPtr+1) ); > } > > can any one explain me the o/p ?? > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Cheers, Vicky -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
