the questions were same for intern as well as for placement except for
last one i.e design question which was not there for intern.

On Sat, Jul 23, 2011 at 5:27 PM, arun kumar <[email protected]> wrote:
> @ shady:the algo posted by naveen ms is better than eulicd algorithm
> to find gcd. for more details refer
> http://en.wikipedia.org/wiki/Binary_GCD_algorithm
>
> On Sat, Jul 23, 2011 at 5:20 PM, shady <[email protected]> wrote:
>> gcd can always be found in O(log(larger number)) using Euclidean algorithms
>> , couldn't understand the complexity in that ???? what's the meaning of
>> O(log UV)^2 ?
>>
>> On Sat, Jul 23, 2011 at 5:14 PM, dilip makwana <[email protected]>
>> wrote:
>>>
>>> @Akshata Sharma
>>>
>>> (2) double full(double a)
>>> {
>>>    return (int)(a+0.5);
>>> }
>>>
>>> I tried this on DevC++ , with various inputs ; it is working fine ....
>>>
>>> On 23 July 2011 17:00, Akshata Sharma <[email protected]> wrote:
>>>>
>>>> What about (2)?, will it always work?
>>>>
>>>> On Sat, Jul 23, 2011 at 3:13 AM, prasanth <[email protected]>
>>>> wrote:
>>>>>
>>>>>
>>>>> the CFG was actually
>>>>> s->AB
>>>>> A-> a| BaB
>>>>> B->bbA
>>>>>
>>>>> The false statement i guess was "This grammar doesnt produce a string
>>>>> of 4 consecutive bs"
>>>>>
>>>>>
>>>>> and 2 or 3 questions mainly focused on j&=j-1 guess this unsets the
>>>>> rightmost set bit
>>>>>
>>>>>
>>>>> pointer related questions were asked.One such was
>>>>>
>>>>> (1)int arr[2][3]={{1,2,3},{4,5,6}};
>>>>> int (*ptr)[3]=&a[0];
>>>>> printf("(%d,%d)",(*ptr)[1],(*ptr)[2]);
>>>>> ptr+=1;
>>>>> printf("(%d,%d)",(*ptr)[1],(*ptr)[2]);
>>>>>
>>>>> find the output???
>>>>>
>>>>> (2) double full(double a)
>>>>> {
>>>>>    return (int)(a+0.5);
>>>>> }
>>>>>
>>>>> does this always work??
>>>>>
>>>>> (3) int x=123,y=231;
>>>>>    int t=0;
>>>>>    int l;
>>>>>    l=x^y;
>>>>>    while(l)
>>>>>    {
>>>>>        t++;
>>>>>        l&=l-1;
>>>>>    }
>>>>>    printf("%d",t);
>>>>>
>>>>> --
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>>>>
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>>>
>>>
>>>
>>> --
>>> Dilip Makwana
>>> VJTI
>>> BTech Computers Engineering
>>> 2009-2013
>>>
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>>
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>

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