But the argument to the function is passed as a pointer to an object not by value then why its not working..
On Thu, Jul 21, 2011 at 5:45 PM, dinesh bansal <[email protected]> wrote: > Value which is changed inside a function will not be reflected after call. > So you are setting b as pointer to class a but this value will not retain > after function call in main(). > > > > On Thu, Jul 21, 2011 at 5:40 PM, Saurabh <[email protected]> wrote: > >> Can any one explain why the following program not giving the correct >> output. >> >> #include <iostream> >> using namespace std; >> class a >> { >> int x; >> >> public: >> void set(int y) >> { >> x=y; >> } >> int get() >> { >> return x; >> } >> >> }; >> void f(a * b) >> { >> b = new a(); >> b->set(5); >> } >> int main() >> { >> a *a1; >> f(a1); >> cout<<"x = "<<a1->get(); >> return 0; >> } >> >> >> >> -- >> Regards >> Saurabh >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> > > > > -- > Dinesh Bansal > The Law of Win says, "Let's not do it your way or my way; let's do it the > best way." > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- Regards n Luv Saurabh Badhai -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
