good solution

On Wed, Jul 20, 2011 at 6:23 PM, ~*~VICKY~*~ <[email protected]>wrote:

> @Deepthi: Thanks a lot :)
>
>
> On Wed, Jul 20, 2011 at 11:33 AM, Deepthi Srinivasan 
> <[email protected]>wrote:
>
>> @Vicky
>> Piyush's algo is based on a little trick to determine divisibility by 3.
>> Number of bits set in odd position - Number of bits set in even position 'll
>> be divisible by 3
>> For example, take 9. 1001. No. of bits set in odd position - number of
>> bits set in even position is 0. Hence divisible by 3.
>> For 21, 10101. Difference is 3.. SO just keep count of the number of bits
>> set in odd position and even position as the stream
>> progresses and ur done...
>>
>>
>> On Tue, Jul 19, 2011 at 10:35 PM, SAMM <[email protected]> wrote:
>>
>>> find the difference between the set bits in the odd and even position,
>>> if this diff is divisible by 3, then it is the multiple of 3..
>>>
>>> On 7/20/11, ~*~VICKY~*~ <[email protected]> wrote:
>>> > @Piyush Sinha:
>>> >
>>> > Can u plz state an example? I don get ur algo
>>> >
>>> > On Wed, Jul 20, 2011 at 12:52 AM, SAMM <[email protected]>
>>> wrote:
>>> >
>>> >> The above method is good , I was going to suggest another algo it
>>> >> takes the same complexity but lengthy so I am not posting my algo...
>>> >>
>>> >> On 7/19/11, Piyush Sinha <[email protected]> wrote:
>>> >> > Divisibility of 3 of numbers in base 2 can be seen same as
>>> >> > divisibility of numbers by 11 in base 10...
>>> >> >
>>> >> > maintain two variable even_sum & odd_sum, both initialized to 0
>>> >> >
>>> >> > when an odd location in the number is set increment odd_sum
>>> >> > when an even location in the number is set increment even_sum
>>> >> >
>>> >> > if(abs(even_sum-odd_sum)%3==0) number is divisible by 3...
>>> >> >
>>> >> > Hence keep the track of even_sum and odd_sum as the bits are getting
>>> >> > appended..
>>> >> >
>>> >> > Hope I am clear... :)
>>> >> >
>>> >> > On 7/19/11, sudhanshu pandey <[email protected]> wrote:
>>> >> >> use automata theory. draw dfa for divisibility by 3..
>>> >> >>
>>> >> >> On Tue, Jul 19, 2011 at 11:23 PM, siva viknesh
>>> >> >> <[email protected]>wrote:
>>> >> >>
>>> >> >>> Given an infinite stream of bits with bits being appended at the
>>> >> >>> highest significant position. Give an algorithm to say whether the
>>> >> >>> number formed by sequence of bits that had been processed till
>>> then ,
>>> >> >>> is divisible by 3 or not ?
>>> >> >>>
>>> >> >>>
>>> >> >>> My sol:
>>> >> >>>
>>> >> >>> have a variable sum.......find the sum of bits....whenever u add a
>>> bit
>>> >> >>> do sum+="bit value"  ... check whether sum%3==0.....
>>> >> >>> ....Is my solution ok?? anyother good solutions ??
>>> >> >>>
>>> >> >>> --
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>>> >> >>>
>>> >> >>>
>>> >> >>
>>> >> >>
>>> >> >> --
>>> >> >> SUDHANSHU PANDEY
>>> >> >>
>>> >> >> --only fair thing in this world is a chance--
>>> >> >>
>>> >> >> --
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>>> >> >>
>>> >> >>
>>> >> >
>>> >> >
>>> >> > --
>>> >> > *Piyush Sinha*
>>> >> > *IIIT, Allahabad*
>>> >> > *+91-7483122727*
>>> >> > * <https://www.facebook.com/profile.php?id=100000655377926> "NEVER
>>> SAY
>>> >> > NEVER"
>>> >> > *
>>> >> >
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>>> >> >
>>> >>
>>> >>
>>> >> --
>>> >> Somnath Singh
>>> >>
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>>> >>
>>> >>
>>> >
>>> >
>>> > --
>>> > Cheers,
>>> >
>>> >   Vicky
>>> >
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>>> >
>>>
>>>
>>> --
>>> Somnath Singh
>>>
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>
>
>
> --
> Cheers,
>
>   Vicky
>
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-- 
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD

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