take two ptrs ptr1 and ptr2 pointing to head
move ptr1 until 1/4th of size of list.
move ptr1 and ptr2 until ptr1=null
ptr2 is pointing at 3/4th

surender

On Tue, Jul 19, 2011 at 3:42 PM, SAMMM <[email protected]> wrote:

> Yaa this will work , you need to handle the case for odd number of
> nodes .
> For even number of node it will serve the purpose .
>
> Yaa for the second part also you can use the ratio concept
>
> fast pointer : slow pointer = 4:3
>
> slow = ptr->next->next->next
> fast = ptr->next->next->next->next
>
>
> Here also we need to handle the case if the number of node is not a
> multiple of 4 .
>
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