the output will be (b)
before looking for the reason, you should know the syntax of printf
*int printf(const char *format,....)*
the function at the string after the comma operator only if the format
string aks for any format specifier like %d or %f etc...u can try it like
this also in normal main function
*printf("piyush","sinha");
*It wil compile and run successfully...and u can guess the output too.... :)
*
*
On Mon, Jul 18, 2011 at 2:19 AM, aditi garg <[email protected]>wrote:
> #include<stdio.h>
> #define FUN(arg) do\
> {\
> if(arg)\
> printf("have fun...","\n");\
> } while(i--)
> void main()
> {int i=2;
> FUN(i<3);
> }
>
> A.have fun..
> have fun..
> have fun..
> B.have fun..have fun..have fun..
> C.Error : cannot use instructions in macro
> D.No output
>
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--
*Piyush Sinha*
*IIIT, Allahabad*
*+91-7483122727*
* <https://www.facebook.com/profile.php?id=100000655377926> "NEVER SAY
NEVER"
*
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