@sourabh are you sure the code
int main()
{
g();
f();
}
inline int f(){
g();
return g()+1;
}
inline int g()
{
return 1;
}
does work i think i must give compilation error.
Because a function need to be declared, before it is called in case of c++.
and by inline the code in the function is replaced when it is called.
On Wed, Jun 8, 2011 at 8:31 PM, hary rathor <[email protected]> wrote:
> because compiler have know about g funtion while evaluating f
>
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