#include<stdio.h>
#include<stdlib.h>
struct node
{
int data;
struct node *left;
struct node *right;
}*root=NULL;
main()
{
root=(struct node *)malloc(sizeof(struct node));
root->data=10;
root->left=NULL;
root->right=NULL;
printf("&root->%x--root-->%x--*root-->%d--&(root->data)=%x--&(root->left)=%x--&(root-->right)=%x",&root,root,*root,&(root->data),&(root->left),&(root->right));
}
In this,program,i try to print address of struct members but it print zero
for &(root->data) and &(root->left).it also print same value for root and
&(root->right).so anyone one can explain me in detail how struct members
stored in memory.
--
**Regards
SAGAR PAREEK
COMPUTER SCIENCE AND ENGINEERING
NIT ALLAHABAD
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