@dheeraj: but the prototypes are same..... how u are calling it overloading plz explain
On 7/12/11, dheeraj tyagi <[email protected]> wrote: > const means that it cannot be overloaded..i think due to that this is > happening. > > On Tue, Jul 12, 2011 at 9:26 PM, segfault <[email protected]> wrote: > >> #include<iostream> >> using namespace std; >> class x{ >> public: >> x() {} >> >> int func() const{ >> cout<<"it is const function\n"; >> } >> >> int func() { >> cout<<"it is simple functin\n"; >> } >> >> >> }; >> int main() >> { >> x a; >> a.func(); >> return 0; >> } >> >> why cann't it take const function? >> explain it >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > > -- > With regards > Dheeraj Tyagi > 8197218001 > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
