what abt this... check length of the array if same then we make a min heap of both the arrays which can be done in O(n) and call extraxtmin(). in this way we can find whether they r equal. othwersie nt equal.
correct me if i am wrong!! On Mon, Jul 4, 2011 at 4:35 AM, saurabh singh <[email protected]> wrote: > Lets conclude this post.Shall we? > .An o(n) seems infeasible without any significant extra memory.... > If extra memory is allowed,hash maps can be used to bring it down to > o(logn).But hash maps would eat up serious memory if numbers occupy a large > range. > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
