I have solved this using one malloc find the code in http://ideone.com/BV9Kj
On Thu, Jun 30, 2011 at 1:20 AM, Piyush Sinha <[email protected]> wrote: > ohh sorry....my bad...i didnt read the whole question..i just read the > subject...:P > > i think its not possible if u want other than hary's solution... > > On 6/30/11, Apoorve Mohan <[email protected]> wrote: >> @piyush: only one call to malloc...ur sol has 2 >> >> On Thu, Jun 30, 2011 at 12:58 AM, Piyush Sinha >> <[email protected]>wrote: >> >>> int **p; >>> p = (int **)malloc(sizeof(int *)*row); >>> for(i = 0;i<row;i++) >>> p[i] = (int *)malloc(sizeof(int)*column); >>> >>> On 6/30/11, Apoorve Mohan <[email protected]> wrote: >>> > though thankx :) >>> > >>> > On Thu, Jun 30, 2011 at 12:44 AM, Apoorve Mohan >>> > <[email protected]>wrote: >>> > >>> >> @above: man i need a 2d array not a 1d array... >>> >> >>> >> >>> >> On Thu, Jun 30, 2011 at 12:38 AM, hary rathor >>> >> <[email protected]>wrote: >>> >> >>> >>> >>> >>> #include<stdlib.h> >>> >>> >>> >>> int main () >>> >>> { >>> >>> int *mat; >>> >>> int i,j; >>> >>> int ROW=4; >>> >>> int COL=3; >>> >>> int k=0; >>> >>> mat=(int *)malloc(ROW*COL*sizeof(int)); >>> >>> >>> >>> for(i=0;i<ROW;i++) >>> >>> for(j=0;j<COL;j++) >>> >>> mat[i*COL+j]=++k; >>> >>> >>> >>> for(i=0;i<ROW;i++) >>> >>> for(j=0;j<COL;j++) >>> >>> printf("%d,",mat[i*COL+j]); >>> >>> >>> >>> return 0; >>> >>> >>> >>> } >>> >>> >>> >>> >>> >>> >>> >>> -- >>> >>> You received this message because you are subscribed to the Google >>> Groups >>> >>> "Algorithm Geeks" group. >>> >>> To post to this group, send email to [email protected]. >>> >>> To unsubscribe from this group, send email to >>> >>> [email protected]. >>> >>> For more options, visit this group at >>> >>> http://groups.google.com/group/algogeeks?hl=en. >>> >>> >>> >> >>> >> >>> >> >>> >> -- >>> >> regards >>> >> >>> >> Apoorve Mohan >>> >> >>> >> >>> > >>> > >>> > -- >>> > regards >>> > >>> > Apoorve Mohan >>> > >>> > -- >>> > You received this message because you are subscribed to the Google >>> > Groups >>> > "Algorithm Geeks" group. >>> > To post to this group, send email to [email protected]. >>> > To unsubscribe from this group, send email to >>> > [email protected]. >>> > For more options, visit this group at >>> > http://groups.google.com/group/algogeeks?hl=en. >>> > >>> > >>> >>> >>> -- >>> *Piyush Sinha* >>> *IIIT, Allahabad* >>> *+91-8792136657* >>> *+91-7483122727* >>> *https://www.facebook.com/profile.php?id=100000655377926 * >>> >>> -- >>> You received this message because you are subscribed to the Google Groups >>> "Algorithm Geeks" group. >>> To post to this group, send email to [email protected]. >>> To unsubscribe from this group, send email to >>> [email protected]. >>> For more options, visit this group at >>> http://groups.google.com/group/algogeeks?hl=en. >>> >>> >> >> >> -- >> regards >> >> Apoorve Mohan >> >> -- >> You received this message because you are subscribed to the Google Groups >> "Algorithm Geeks" group. >> To post to this group, send email to [email protected]. >> To unsubscribe from this group, send email to >> [email protected]. >> For more options, visit this group at >> http://groups.google.com/group/algogeeks?hl=en. >> >> > > > -- > *Piyush Sinha* > *IIIT, Allahabad* > *+91-8792136657* > *+91-7483122727* > *https://www.facebook.com/profile.php?id=100000655377926 * > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > > -- Thanks and regards Rizwan A Hudda http://sites.google.com/site/rizwanhudda2 -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
