Please see this.
http://ideone.com/ZM74d
<http://ideone.com/ZM74d>I tried to print by directly giving 2[*arr] still
it's giving null and 0.000.
Can anyone think of a possible reason?

On Fri, Jun 24, 2011 at 8:27 PM, rajeev bharshetty <[email protected]>wrote:

> @ T3rminal That is because the term is resolved as 2[*arr] which is
> pointing to the structure variable 'c' of type 'job' So 'n' format
> specifiers should be used to print n values of a structure and that to in
> sequence of declarations in the structure .
>
>
> Hope this helps :)
>
>
> Regards
>
>
> Rajeev N B
>
> I Blog @ www.opensourcemania.co.cc
>
> On Fri, Jun 24, 2011 at 4:10 AM, T3rminal <[email protected]> wrote:
>
>> How  printf can print 2 values for %s and %f if you provided only 1
>> (3,x>>1)[*arr] ?
>>
>> On Jun 24, 12:13 am, Anika Jain <[email protected]> wrote:
>> > #include<stdio.h>
>> > typedef struct
>> > {
>> >       char *name;
>> >        double salary;}job;
>> >
>> > main()
>> > {
>> >     static job a={"tcs",15000.0};
>> >     static job b={"ibm",25000.0};
>> >     static job c={"google",35000.0};
>> >     int x=5;
>> >     job *arr[3]={&a,&b,&c};
>> >      printf("%s %f\t",(3,x>>1)[*arr]);
>> >
>> > }
>> >
>> > it is giving google 35000.000000 there's no error.. i think u r doing
>> some
>> > mistake by not writing %s as format specifier in printing..
>> > On Thu, Jun 23, 2011 at 8:20 AM, Piyush Sinha <[email protected]
>> >wrote:
>> >
>> >
>> >
>> >
>> >
>> >
>> >
>> > > even I am getting output as google 0.00000
>> >
>> > > On 6/23/11, Bhavesh agrawal <[email protected]> wrote:
>> > > > i got (null) 0.00000 on my gcc compiler , is there any syntax error
>> >
>> > > > --
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