Sorry. Ignore the last message of mine. It does not belong to this thread.
:)

On Fri, Jun 24, 2011 at 8:37 PM, oppilas . <[email protected]>wrote:

> Please see this.
> http://ideone.com/ZM74d
> <http://ideone.com/ZM74d>I tried to print by directly giving 2[*arr] still
> it's giving null and 0.000.
> Can anyone think of a possible reason?
>
>
> On Fri, Jun 24, 2011 at 12:55 AM, richa mahajan <[email protected]>wrote:
>
>> i think it ll be compiler dependent becoz comma acts as a sequence pooint
>> but not in function calls so semi colon here is a sequnce point and d value
>> of an object (ptr here) is being modified more than once (between two seq
>> points ) so this is undefined behavior..output will b compiler dependent
>>
>>
>> On Wed, Jun 22, 2011 at 5:55 PM, udit sharma <[email protected]>wrote:
>>
>>> #include<stdio.h>
>>> int main()
>>> {
>>> void print(int *,int *,int *,int *,int *);
>>> static int arr[]={97,98,99,100,101,102,103,104};
>>> int *ptr=arr+1;
>>> print(++ptr,ptr--,ptr,ptr++,++ptr);
>>> return 0;
>>> }
>>> void print(int *a,int *b,int *c,int *d,int *e)
>>> {
>>> printf("%d\t%d\t%d\t%d\t%d\n",*a,*b,*c,*d,*e);
>>> }
>>>
>>> Why the output is:
>>> 100    100    100    99    100
>>>
>>>
>>> --
>>> Regards
>>>  UDIT
>>>  DU- MCA
>>>
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>
>

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