@piyush Because of its interpretation as ascii .The character's ascii value is taken into account which is an integer .
On Thu, Jun 23, 2011 at 6:32 PM, piyush kapoor <[email protected]> wrote: > int main() > { > char a; > printf("%d %d",sizeof(a),sizeof('a')); > return 0; > } > Output: > 1 4 > > why does the expression sizeof('a') evaluates it as an integer,not as a > character?? > -- > *Regards,* > *Piyush Kapoor,* > *CSE-IT-BHU* > > -- > You received this message because you are subscribed to the Google Groups > "Algorithm Geeks" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/algogeeks?hl=en. > -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
