sorry i did some blunders
but finally got my code working :)
#include<iostream>
using namespace std;
void func(int a,int b,char *str)
{
if(a==0&&b==0)
{str[4-(a+b)]='\0';cout<<str<<"\n";return;}
if(a>0)
{
str[4-(a+b)]='(';
func(a-1,b,str);
}
if(b>a)
{
str[4-(a+b)]=')';
func(a,b-1,str);
}
}
int main()
{
char str[10];
func(2,2,str);
return 0;
}
On Fri, Apr 15, 2011 at 8:44 PM, Harshit Gangal <[email protected]>wrote:
> there are two if statements and not an id else statement.
> so in first case a is modified and then next if statement is checked
> against b>a
> whereas in 2nd case a is not modified and checkd with the same value for
> the second if statement
>
> On Fri, Apr 15, 2011 at 8:39 PM, priya mehta
> <[email protected]>wrote:
>
>> http://www.ideone.com/IKM57
>>
>> http://www.ideone.com/PmJ7A
>> there is a minor change between the codes
>> one works another doesn't
>> someone please tell the reason
>>
>> On Fri, Apr 15, 2011 at 8:38 PM, priya mehta <[email protected]>wrote:
>>
>>> http://www.ideone.com/PmJ7A
>>>
>>>
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>
>
>
> --
> Harshit Gangal
> Fourth Year Undergraduate Student
> Dept. of Computer Science
> JIIT, Noida , India
>
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