@AAmir: The easiest way is to declare A as long long int. Be sure to change the printf format string.
Dave On Apr 14, 8:31 am, AAMIR KHAN <[email protected]> wrote: > #include<cstdio> > #define MOD (int)1e9 > using namespace std; > int main() { > int A = 33554432; > printf("%d\n",A*A); > printf("%d\n",((A*A)%MOD)); > return 0; > > } > > How can i calculate, lets say last 9 digits of square of 33554432 ? > > Thanks, > Aamir -- You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/algogeeks?hl=en.
