@Sravan: Plz explain the logic..

On 12/15/10, Sravan Akepati <[email protected]> wrote:
> (1-0.25)* 0.75*5000 = 2812.5
>
> On Wed, Dec 15, 2010 at 9:31 AM, ankit sablok <[email protected]> wrote:
>
>> well i still believe that the calling of foo2 is independent plzzz suggest
>> me the solution if i am wrong a detailed one thanx in advance
>>
>>
>> On Wed, Dec 15, 2010 at 1:22 AM, Saurabh Koar
>> <[email protected]>wrote:
>>
>>> The function foo2 will be called iff the condition if(C<D) evaluates to
>>> be
>>> true.
>>> Given that C<D turns out to be true 75% times.So why the call to foo2
>>> will be independent??
>>> I think it is only the simple math.Correct me if I am wrong..
>>>
>>> On 12/15/10, ankit sablok <[email protected]> wrote:
>>> > what i think is that the number of times foo2 being called is
>>> > independent of the percentages given in the question it may be called
>>> > 5000 times or 4999 times and continuinf in this fashion also none of
>>> > the times as in every case there's 1/4 probability of A<B and 3/4 of
>>> > C<D so as per me we cannot decide givn the percentage of success and
>>> > failure any suggestions are always welcomed
>>> >
>>> > On Dec 15, 12:06 am, bittu <[email protected]> wrote:
>>> >> void foo1()
>>> >> {
>>> >>   if(A<B)
>>> >>     Then {_/*.... */}
>>> >>   else
>>> >>    if(C<D)
>>> >>      then foo2()
>>> >>
>>> >> }
>>> >>
>>> >> How many time foo2() would get called given
>>> >> A<B 25% of the times and C<D 75% of the times and foo1() is called
>>> >> 5000 times
>>> >>
>>> >> although i had diff...solution..but i wants to confirm wid others..so
>>> >> hav a look
>>> >>
>>> >> Regards
>>> >> Shashank Mani
>>> >> BIT Mesra
>>> >
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