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lets have another approach,tell me if it works

Notice that the number of digits used to represent an n^3 different numbers
in a k-ary number system is d= log(n^3) base k.

Thus considering then 3 numbers as radix n numbers gives us that:

d=log (n^3)base n= 3logn(n)= 3

Radix sort will then have a running time ofΘ(d(n+ k)= Θ(3(n+ n)) = Θ(n)


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