how will this give me array_1 which lists all numbers comming 1 time ,
array_2 which lists all numbers comming 2  time  etc ?


On Sun, Oct 3, 2010 at 11:31 AM, kusuma sanjeev <[email protected]>wrote:

> One possible solution would be to create an array of pointers to the list..
> array index indicates how many times the element occurs and the list gives
> the elements.
>
>
> On Sun, Oct 3, 2010 at 11:22 AM, sharad kumar <[email protected]>wrote:
>
>> it will take same amount of memory na....key value is element and vaule is
>> the amount of times element occurs.....
>>
>>
>> On Sun, Oct 3, 2010 at 11:11 AM, mac adobe <[email protected]> wrote:
>>
>>> i think hash map takes lots of memory ...  please correct me if i am
>>> wrong here ..
>>>
>>> anyways its a soluton but i would like to have a different solution .. :)
>>>
>>>
>>> --mac
>>>
>>>
>>> On Sun, Oct 3, 2010 at 10:55 AM, sharad kumar 
>>> <[email protected]>wrote:
>>>
>>>> cant u use a hash map buddy???
>>>>
>>>>   On Sun, Oct 3, 2010 at 10:35 AM, mac adobe <[email protected]>wrote:
>>>>
>>>>>  You are given a very long array of integers . Some number in this
>>>>> integer array come 1 time , some 2 times some 3 times . create 3 different
>>>>> arrays .
>>>>> Array 1 will have numbers with numbers comming only1 time , Array 2
>>>>> will have numbers with numbers comming 2  times, Array 3 will have numbers
>>>>> with numbers repearting 3 times ,
>>>>>
>>>>>
>>>>> Can you extend the solution to create array_x with elements  repeating
>>>>> x times ?
>>>>>
>>>>> thanks
>>>>> --mac
>>>>>
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>>>>
>>>>
>>>> --
>>>> yezhu malai vaasa venkataramana Govinda Govinda
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>> yezhu malai vaasa venkataramana Govinda Govinda
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>
>
>
> --
> Rgds,
> Kusuma S
>
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-- 
thanks
--mac

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