If a and b are the numbers then
dig = log10(a) + log10(b);
if dig has some fractional part then number of digits is dig + 1 else dig.

On Mon, Sep 20, 2010 at 11:19 AM, sumant hegde <[email protected]> wrote:

>
> Adding to the partial solution, if x, y are first digits, and  x*y + x + y
> < 10, the result will be  a+b -1 digits. "If not, u will need a complex
> logic to solve"
>
> On Mon, Sep 20, 2010 at 10:50 AM, rahul patil <
> [email protected]> wrote:
>
>> A partial solution is , if you multiply first digits of  two nos  and
>> result is greater than 10 then surely result will be a+b digits
>> If not, according to me, u will need a complex logic to solve.
>>
>>
>> On Mon, Sep 20, 2010 at 10:41 AM, Srinivas <[email protected]
>> > wrote:
>>
>>> how to find the no. of digits in the product of two numbers without
>>> multiplying??
>>> if a is the number of digits in A and
>>> if b is the number of digits in B
>>> the number of digits in A*B is either a+b or a+b-1 but how to find the
>>> exact one?
>>>
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>>
>>
>> --
>> Regards,
>> Rahul Patil
>>
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