A nice explaination at

http://www.rawkam.com/?p=351

On Tue, Aug 24, 2010 at 6:49 PM, Chandan Balu <[email protected]> wrote:

> Can somebody please tell me, how does the above code for permutation
> works(Algorithms behind) please?
>
>
> On Mon, Aug 2, 2010 at 4:31 AM, bujji <[email protected]> wrote:
>
>>
>> Here is simple code to generate permutations
>>
>> #include "stdafx.h"
>>
>> #include<stdio.h>
>>
>>  int Permute( char *, int);
>>
>> int PrintArray();
>>
>> int swap(char *, int);
>>
>> char A[]={'1','2','3','4','5','6','7','8'};
>>
>>
>>
>> main( )
>>
>> {
>>
>>
>>      Permute(A,sizeof(A)/sizeof(char));
>>
>>      return 0;
>>
>> }
>>
>>
>>
>> int Permute(char * a, int n)
>>
>> {      if(n==1)
>>
>>      {     PrintArray();
>>
>>            return 0;
>>
>>      }
>>
>>      int i=0;
>>
>>      for(i=0; i<n;i++)
>>
>>      {
>>
>>            swap(a,i);
>>
>>            Permute(a+1,n-1);
>>
>>            swap(a,i);
>>
>>      }
>>
>> }
>>
>>
>>
>> int PrintArray()
>>
>> {
>>
>>      int i=0;
>>
>>      static int Number_of_Solutions=0;
>>
>>      printf("\n  Conf: %-4d  ",++Number_of_Solutions);
>>
>>      for(i=0;i<sizeof(A);i++)
>>
>>            printf("%c ",A[i]);
>>
>>
>>
>>      return 0;
>>
>> }
>>
>>
>>
>> int swap( char *a, int i)
>>
>> {
>>
>>      if(i<0)
>>
>>            return -1;
>>
>>      int temp=*a;
>>
>>      *a=a[i];
>>
>>      a[i]=temp;
>>
>>
>>
>>      return 0;
>>
>> }
>>
>>
>> Regards,
>> Bujji
>>
>>
>> On Aug 1, 4:00 pm, UMESH KUMAR <[email protected]> wrote:
>> >  Write a C  code for generate all possible Permutation
>> >  as:- 1 2 3
>> > Total no. of Per=6
>> > also print all permutation
>> > as:- 1 2 3
>> >        1 3 2
>> >         2 1 3
>> >        2 3 1
>> >        3 1 2
>> >       3 2 1
>> > if inpute is 1 2 3 2
>> >      total no of permutation = 12
>>
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