dude they dont need to be in the same order ..
how are taking care of that

On Sun, Aug 1, 2010 at 10:47 AM, Anand <[email protected]> wrote:

> Using Dynamic programing(Longest common subsequence logic) we can solve
> this problem in O(nm) where n is the length of the first string and m is the
> length of second string. Last element of matrix which the length of the
> string that matches.
>
> http://codepad.org/cyiKEMSF
>
> <http://codepad.org/cyiKEMSF>
>
> On Sun, Aug 1, 2010 at 8:13 AM, srikanth sg <[email protected]>wrote:
>
>> plz .. if any one knows dp solution then tell ...
>>
>>
>> On Sun, Aug 1, 2010 at 7:31 AM, Ashim Kapoor <[email protected]>wrote:
>>
>>> I am not sure, but can I do this using a suffix trie ? any comments ?
>>>
>>>
>>>
>>>
>>> On Sun, Aug 1, 2010 at 2:29 PM, Ashish Goel <[email protected]> wrote:
>>>
>>>> solution could be to find the charcter position from both sides for each
>>>> char of s2
>>>> then from the 2*n array, find the smallest index from left and largest
>>>> from right, within these two indexes all chars would be there
>>>>
>>>> one case where one of the chars can be missing can be found if a row in
>>>> this 2-d array remains unmodified
>>>>
>>>>
>>>>
>>>> Best Regards
>>>> Ashish Goel
>>>> "Think positive and find fuel in failure"
>>>> +919985813081
>>>> +919966006652
>>>>
>>>>
>>>>
>>>> On Sat, Jul 31, 2010 at 10:22 PM, Nikhil Jindal <[email protected]
>>>> > wrote:
>>>>
>>>>> At the moment, I can only think of an O(n^3) algo.
>>>>> Maybe if you can find a hash function which computes the hash value
>>>>> depending on the unique characters the string contains, you can reduce it 
>>>>> to
>>>>> O(n^2).
>>>>>
>>>>>
>>>>> On Sat, Jul 31, 2010 at 7:09 PM, srikanth sg <[email protected]
>>>>> > wrote:
>>>>>
>>>>>> given two string , find the minimum  width in string 1 containing the
>>>>>> all characters of string 2 , they may present in different order
>>>>>> string 1-HELLO
>>>>>> string 2- LE
>>>>>> answer-2
>>>>>>
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