if adjacency matrix is given then try to check if adj[i][j]==1 and
adj[j][i]==1

On Sat, Jul 10, 2010 at 9:24 AM, Amit Jaspal <[email protected]>wrote:

> @ jalaj
> consider a graph
>
> 2->1
> 3->1
> 2->3
>
> apply dfs(1) n dfs(2)...
> will give u 2 components although GRAPH is connected....
>
>
> On Fri, Jul 9, 2010 at 10:23 PM, jalaj jaiswal 
> <[email protected]>wrote:
>
>>
>> int count=0;
>> for every vertex v{
>>      if visited[v]==0
>>           dfs(v)
>>           count++;
>>      }
>> count is the number of components in graph........ or m i missing
>> something ?
>>
>>
>> On Fri, Jul 9, 2010 at 9:23 PM, amit <[email protected]> wrote:
>>
>>> How to check if a directed graph is connected.
>>>
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>>
>>
>> --
>> With Regards,
>> Jalaj Jaiswal
>> +919026283397
>> B.TECH IT
>> IIIT ALLAHABAD
>>
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