reverse full array first
then, reverse last k elemnts and initial n-k elements seperately
this will do
On Fri, Jul 2, 2010 at 8:34 PM, Ratnesh Thakur <[email protected]>wrote:

> correction..
> a[j]=a[j-1] instead of a[i]=a[i-1]
>
>
> On Fri, Jul 2, 2010 at 7:30 PM, Ratnesh Thakur 
> <[email protected]>wrote:
>
>> i think this should work.
>>
>>
>> for(i=1;i<=k;i++)
>> {
>> var=a[n-1]
>> for(j=n-1;j>=1;j--)
>> a[i]=a[i-1]
>> a[0]=var
>>
>> }
>>
>> On Fri, Jul 2, 2010 at 5:36 PM, Saurabh Ahuja <[email protected]>wrote:
>>
>>> a[0] = a[2]
>>> a[1] = a[3]
>>> a[2] = a[4]
>>>
>>> a[0] and a[1] has been changed
>>> a[3] = a[0]
>>> a[4] = a[1]
>>>
>>> so this solution would not work.
>>>
>>>
>>> On Fri, Jul 2, 2010 at 5:14 PM, Akash Gangil <[email protected]>wrote:
>>>
>>>> wouldn't this work:
>>>>
>>>>
>>>>
>>>> for i in range(0,len)
>>>>     a[i] = a[(i+2)%5];
>>>>
>>>> where len is the length of array
>>>>
>>>>
>>>> On Sat, Jun 26, 2010 at 3:37 PM, sharad kumar <[email protected]
>>>> > wrote:
>>>>
>>>>> i have to right rotate an array by k positions
>>>>> 1 2 3 4 5 for k=2 o/p shud be
>>>>> 3 4 5 1 2
>>>>>
>>>>>
>>>>> P.S---do not give block reversal method for array rotation and soln
>>>>> must be inplace.....plzz write ur logic also along with d code
>>>>>
>>>>> --
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>>>>
>>>>
>>>>
>>>> --
>>>> Best Regards
>>>> Akash Gangil
>>>>
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>>
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+919026283397
B.TECH IT
IIIT ALLAHABAD

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