just check the signs of the i, j components of vector from the centre of
screen to (x,y)
pseudo code:-
getQuadrant(x,y){
string Q[]={"1st","4th","2nd", "3rd"};
vx=(x>=midx)?0:1
vy=(y>=midy)?0:1
return Q[(vx<<1)|vy]
}
Anurag Sharma
On Mon, Jun 14, 2010 at 5:55 PM, siddharth srivastava
<[email protected]>wrote:
> I have this code snippet:
> This code snippet defines a boundary coordinates on the screen wrt to the
> center(of the screen).
>
> if( x < x_center )
> x_border = x_center - x_shift;
> else
> x_border = x_center + x_shift;
>
> if( y < y_center )
> y_border = y_center - y_shift;
> else
> y_border = y_center + y_shift;
>
> //x_shift and y_shift are constants.
>
> What is the best possible way to determine in which quadrant( wrt to the
> center) the point (x,y) lies ?
>
>
> Siddharth Srivastava
>
>
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