#include<iostream>
using namespace std;
int main(){
int a[4][4]={1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16};
int i=0,j,n=3,l=0,m=n;
j=n;
while(i<=n){
int i1=i,j1=j,k=0,l=n;
for(;k<j1;i1++,j1--){
swap(a[k][i1],a[j1][l]);
if(i!=0){
swap(a[i1][k],a[l][j1]);
}
k++;
l--;
}
i++;
j--;
}
for(i=0;i<4;i++){
for(j=0;j<4;j++){
cout<<a[i][j]<<" ";
}
cout<<endl;
}
return 0;
}
On Mon, Jun 7, 2010 at 8:26 AM, sharad <[email protected]> wrote:
> write a c routine to flip an nXn matrix about its non major diagnol
>
>
> 3 4 5
> 6 7 9
> 1 2 8
>
> Transpose is:
> 8 9 5
> 2 7 4
> 1 6 3
>
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