If you need an array large enough to hold all tree elements, that is
not constant space, it is O(n) space.

On May 14, 5:47 am, divya jain <[email protected]> wrote:
> form a sorted  array from inorder traversal of tree. now take to pointers
> one to the beginning of array and other at the end. now check if the sum of
> element is greater than reqd sum then increment 1st ptr. if their sum is
> less than reqd sum then decrement 2nd ptr. if their sum is equal to the reqd
> sum then this is the ans..
> hope it will work..
>
> On 13 May 2010 20:11, jalaj jaiswal <[email protected]> wrote:
>
>
>
> > given a bst... find two nodes whose sum is equal to a number k ... in O(n)
> > time and constant space...
>
> > --
> > With Regards,
> > Jalaj Jaiswal
> > +919026283397
> > B.TECH IT
> > IIIT ALLAHABAD
>
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