@all
i think all the above approaches are greedy..
we need dynamic solution to this problem..


On Sat, Feb 13, 2010 at 11:42 AM, vikrant singh <[email protected]>wrote:

> @sachin : the problem is bit more complex , consider N be 2 , and
> coordinates be (-2,0) (0,0) (1,0) (3,0). your solution( min value=1+5=6)
> wont give the right answer(2+2=4).
>
>
> On Sat, Feb 13, 2010 at 6:07 PM, sachin <[email protected]> wrote:
>
>> We can make a spanning tree for these 2N points and then find the
>> minimum spanning tree
>> keeping in mind that a node can only be considered in one edge and not
>> more than once.
>> This will give you the minimum total sum of all the pairs.
>> You can use kruskal's min spanning tree algorithm to find the minimum
>> spanning tree because
>> kruskal's method works by finding the least cost edges & then
>> proceeding towards the max cost edges.
>> I hope it solves your problem.
>>
>> Regards,
>> Sachin
>>
>>
>> On Feb 12, 9:20 am, GentLeBoY <[email protected]> wrote:
>> > given 2N points in a plane. Pair up to obtain N distinct pairs such
>> > that total sum of paired distances is minimum.
>> > N can be atmost 50.
>>
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>
>
> --
> Vikrant Singh
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