Thank you! Just responded with complete DEBUG level log privately. On Tuesday, December 7, 2021 at 10:44:02 AM UTC+2 adsapi wrote:
> Hi Oksana, > > > > Thank you for providing the requested information. However, the logging > level of your Google Ads API request seems to only be at INFO level. We > would need the logs at DEBUG level in order to further investigate the > issue. As previously adviced by my colleague, logging instructions can be > found by navigating to the Client libraries > Your client library (ex. > Java) > Logging documentation, which you can access from this *link* > <https://developers.google.com/google-ads/api/docs/client-libs>. You may > send the logs again to us via *Reply privately to author* option or send > it directly to googleadsa...@google.com. > > > > Also, I've noticed that there's a lot of filters in your AdWords API > report. Please note that when comparing reports between AdWords and Google > Ads APIs, all the fields and filters used should also be the same. > > > > Regards, > [image: Google Logo] > Kevin Gil Soriano > Google Ads API Team > > > ref:_00D1U1174p._5004Q2SbPja:ref > -- -- =~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~ Also find us on our blog: https://googleadsdeveloper.blogspot.com/ =~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~ You received this message because you are subscribed to the Google Groups "AdWords API and Google Ads API Forum" group. To post to this group, send email to adwords-api@googlegroups.com To unsubscribe from this group, send email to adwords-api+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/adwords-api?hl=en --- You received this message because you are subscribed to the Google Groups "AdWords API and Google Ads API Forum" group. To unsubscribe from this group and stop receiving emails from it, send an email to adwords-api+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/adwords-api/bdb70472-ae88-4247-9a55-20c421b280a5n%40googlegroups.com.