Hi Sai,
I wasn't using meda_file.image for an argument. I was pointing that to
asking if the functionality was available. I am writing the code in Scala.
val mediaFile: MediaFile = MediaFile.newBuilder
.setName("myimage")
.setType(MediaType.IMAGE)
.build
val mediaFileOps: java.util.List[MediaFileOperation] = java.util.Arrays.
asList(
MediaFileOperation.newBuilder.setCreate(mediaFile).build
)
val mediaFileServiceClient: MediaFileServiceClient = dependencies.gadsClient
.getMediaFileServiceClient
val response: MutateMediaFilesResponse = mediaFileServiceClient.
mutateMediaFiles('adAccountIdHere', mediaFileOps)
This response returns INVALID_ARGUMENT. Can you explain where the invalid
argument is?
I know I can use the Google UI to upload images, however I do not know how
to retrieve the resource_name from this. Can you explain how I can get the
resource_name from the UI?
Thanks,
John
On Monday, February 4, 2019 at 4:20:06 PM UTC-5, googleadsapi-forumadvisor
wrote:
>
> Hello John,
>
> The resource media_file
> <https://developers.google.com/google-ads/api/docs/fields/media_file> does
> not have the field media_file.image that the reson for INVALID_ARGUMENT
> error, instead you could use the media_file.resource_name
> <https://developers.google.com/google-ads/api/docs/fields/media_file#media_fileresource_name>
> field.
> You can use the UI of Google Ads API to upload the media files. To upload
> media files via Google Ads API you could use MutateMediaFiles operation as
> shown here
> <https://developers.google.com/google-ads/api/reference/rpc/google.ads.googleads.v0.services#mediafileservice>
> .
>
> Regards,
> Sai Teja, Google Ads API Team
>
>
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