I didn't receive it. As far as I know I have 3 email accounts associated with adwords:
seo@ cromarty@ timtesty@ I recently added another account the other day in my attempts to figure this out: analytics@ The domains of the above emails (mibcomputers.ca, yorkregiontraffictickets.ca, gmail.com). I hope it's not m...@aci.on.ca. They got bought out by Rogers two years ago. I haven't had access to that email address since. I really appreciate your help so far. On Dec 17, 6:12 pm, AdWords API Advisor <adwordsapiadvi...@google.com> wrote: > Hi, > > I privately messaged you a few days ago with the email address of the > account that has your current token. If you didn't receive that email > please let me know. > > Best, > - Eric > > On Dec 16, 11:38 am, mib <croma...@mibcomputers.ca> wrote: > > > I'm going in loops here. This is what Google has to say: > > > *"Your token will be sent to your account email address and will also be > > available through your AdWords API Center -- accessible through your My > > Account tab." > > (src:https://adwords.google.com/support/aw/bin/answer.py?hl=en&answer=15104)* > > * * > > * *Ok, I'm logged into the only account that has 'Adwords API Center' under > > the 'My Account' tab. Where is it? > > > * > > > * > > * > > *BTW, when I attempt to reapply I'm denied because "*We’ve received your > > request for a new developer token for the AdWords API. However, during our > > review we found that you already have an approved developer token."* -- =~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~ Also find us on our blog and discussion group: http://adwordsapi.blogspot.com http://groups.google.com/group/adwords-api =~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~=~ You received this message because you are subscribed to the Google Groups "AdWords API Forum" group. To post to this group, send email to adwords-api@googlegroups.com To unsubscribe from this group, send email to adwords-api+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/adwords-api?hl=en
