Why does this not give you the correct answer: Select library_name, count(*) from libvolumes group by library_name
Paul D. Seay, Jr. Technical Specialist Naptheon Inc. 757-688-8180 -----Original Message----- From: Lars Bebensee [mailto:[EMAIL PROTECTED]] Sent: Thursday, September 19, 2002 5:35 AM To: [EMAIL PROTECTED] Subject: Select for Scratches Hi folks, I am not that good with select queries yes, so I will have to ask one of the SQL gurus here: we wanted to show how many scratch tapes each library has with a query like this: "select a.library_name,count(*) as volumes, b.devtype from libvolumes as a, devclasses as b where upper(status) like 'SCRATCH%' and a.library_name='$i' and a.library_name=b.library_name group by a.library_name,b.devtype" $i will be filled with the name of the library before. The funny thing, it shows exactly as twice as many scratches. Is there someone amongst you who can exctract this little monster for me and show me what I am doing wrong. Thanks for helping out Lars
