Your assumption was correct...Collocate will attempt to place every new node onto a
different scratch tape. If the tapepool is at max it will then use existing tapes
defined within the pool.
Larry Way
408-743-4242 Desk
408-655-3512 Cell
408-743-4201 Fax
>>> [EMAIL PROTECTED] 08/28/01 05:15AM >>>
No.....
With collocate you put a maximum of 1 node on 1 tape, so A is not possible,
the 5th node does not have a scratchtape to use.
With collocate every node have's a own set of tape(s), so you need less
mounts when you restore, so the restores are faster. However, the migration
and reclamation takes more time and it takes more tapes. With 12 nodes,
you've got at leased 12 tapes 'filling'.
Greetings,
Maurice van 't Loo
The Netherlands
----- Original Message -----
From: "Robert Ouzen" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, August 28, 2001 9:02 AM
Subject: Question about Maxscratch (Collocate/No Collocate)
> Hi
>
> For example I have two storage pools A and B with:
>
> A with nodes=12 maxscratch=4 collocate=yes
> B with nodes=10 maxscratch=3 collocate=no
>
> My question is about the order of filling the tapes. As I understand
>
> For Storage Pool A : Tape1 Node1 (Scratch 1)
> Tape2 Node2 (Scratch2)
> Tape3 Node3 (Scratch3)
> Tape4 Node4 (Scratch4)
> No more scratch tape (maxscratch=4). Now the next node5 will be on Tape1
and
> node6 on Tape2 etc ........ till nodes12
> The next backup of node1 will be on Tape1 etc .....
>
>
> For Storage Pool B: Tape1 Node1 TO Node10 (scratch 1) till full then
> Tape2 etc .....
>
> Did I understand right ???????????????
>
> T.I.A Regards Robert Ouzen
> E-Mail: [EMAIL PROTECTED]
>
