On Sun, Apr 24, 2011 at 11:03 PM, andrey mirtchovski
<mirtchov...@gmail.com> wrote:
>> #!/usr/local/plan9/bin/9 rc
>> echo first at path: $path(1)
>> for (i in `{seq 1 5}){
>> if (test $i -eq 3) {
>> echo $i equals 3
>> }
>> if not echo $i is different from 3
>> }
>
> NB: in general, you don't need 'test'. use "if (~ $i 3) {}".
>
> that said, now I'm convinced there's a bug somewhere. I got your code
> to fail under the condition that rc is started via the '9' environment
> (9 rc). the type of 'test' binary doesn't matter -- both /bin/test and
> $PLAN9/bin/test break under '9', but don't break without it. the '9'
> script is pretty simple, but there appear do be some side-effects
> (probably due to \r being transmitted over the network?). here's the
> simplest version of your script:
>
> $ cat t.rc
> #!/usr/bin/env rc
> exec rc
> $
>
> dial and test:
>
> $ dial -e 'tcp!localhost!8080'
> ######## no breakage
> /bin/test 1 -eq 2 ; echo $status
> 1
> /bin/test 1 -eq 1; echo $status
>
> /Users/andrey/plan9/bin/test 1 -eq 2; echo $status
> 1
> /Users/andrey/plan9/bin/test 1 -eq 1; echo $status
>
> ######## now see it break
> 9 rc
> /bin/test 1 -eq 2 ; echo $status
>
> /bin/test 1 -eq 1; echo $status
>
> /Users/andrey/plan9/bin/test 1 -eq 2; echo $status
>
> /Users/andrey/plan9/bin/test 1 -eq 1; echo $status
>
> ls | wc > /dev/null; echo $status
> |
> ls | wc > /dev/null; echo $status
> |||
> ls | wc > /dev/null; echo $status
> |||||||
> ls | wc > /dev/null; echo $status
> |||||||||||||||
> ls | wc > /dev/null; echo $status
> |||||||||||||||||||||||||||||||
>
> #####back to non-breaking rc:
> exit
> echo $status
>
> ls | wc > /dev/null; echo $status
> |
> ls | wc > /dev/null; echo $status
> |
> ls | wc > /dev/null; echo $status
> |
> ls | wc > /dev/null; echo $status
> |
> ls | wc > /dev/null; echo $status
> |
>
>
I'm seeing this without the 9. It is a Ubuntu 10.04.2 LTS,
$ uname -a
Linux goitaca 2.6.32-28-generic #55-Ubuntu SMP Mon Jan 10 23:42:43 UTC
2011 x86_64 GNU/Linux
